{"id":10602,"date":"2011-06-26T12:33:23","date_gmt":"2011-06-26T10:33:23","guid":{"rendered":"http:\/\/ylovephoto.com\/en\/?p=10602"},"modified":"2011-06-25T17:37:28","modified_gmt":"2011-06-25T15:37:28","slug":"google-competing-with-tineye","status":"publish","type":"post","link":"https:\/\/www.ylovephoto.com\/en\/2011\/06\/26\/google-competing-with-tineye\/","title":{"rendered":"Google competing with TinEye"},"content":{"rendered":"

Do you remember TinEye<\/a>? This is the company which has been offering since a few years an image search service where you show a photo (or a picture) and they find copies on the web<\/a> (useful for the photographers). This can also help you find the original (useful for webmasters).<\/p>\n

\"\"TinEye was always a little limited by the small number of searched web sites, but the results were absolutely great: They even find look-alikes, pictures that are quite similar but not identical (even deformed, re-colorized, cropped, etc.)<\/p>\n

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Notice the small blue camera<\/figcaption><\/figure>\n

But here comes the web heavy-weight. Competition is going to heat up significantly: Google starts a very similar option in Google Image Search<\/a>, which uses the small blue camera appearing on the right of the search bar when using the Chrome browser<\/a> (and probably all browsers in the near future).<\/p>\n

\"Female<\/a>I tested this image search service to look for an image I know quite well (a giraffe photo I shot in South Africa in 2007 that I know is already quite pirated on the web – I found it in a number of different places but for those interested I have another giraffe photo which is even more pirated even if it is much less beautiful than this one, I think).<\/p>\n

As a photographer, I’d like to find all the people who made a copy of my work and check if -a least- they took the time to attribute it to me (not enough, it’s copyrighted) or to give a link back. For YLovePhoto readers, I thought it would be interesting to do the test, review the results and share my impression about the service.<\/p>\n

There’s no doubt in the results:<\/p>\n